প্রতিদিনের সরকারি চাকুরীর আপডেট পেতে আজই জয়েন করুন
CSIR NET June 2019 Mathematical Sciences Set B
Joint CSIR-UGC NET exam
The CSIR is the Council of Scientific and Industrial Research conducting the Joint CSIR-UGC NET exam twice a year. Now currently, National Testing Agency( NTA) conducts CSIR NET Exam twice a year in June and December. The CSIR NET exam is to be held for determining the eligibility of the candidates for the award of JRF (Junior Research Fellowships) NET and also for providing eligibility for the appointment of Lecturers (NET) in certain subject areas such as Chemical Sciences, Earth Sciences, Life Sciences, Mathematical Sciences, and Physical Sciences.
Joint CSIR UGC NET exam pattern
The Joint CSIR-UGC NET exam pattern for the Single Paper MCQ (Multiple Choice Question)test contains:- The maximum marks for the exam is 200. The time duration of the exam is 3 hours. Three parts are there in the question paper.
Part 'A' is common to all subjects. This part A may contain a maximum of 20 questions of General Aptitude. The candidates are requested to answer any 15 questions from the 20 questions. Two marks are to be awarded for each question. The total marks for Part 'A' are 30 (out of 200).
Part 'B' may contain subject-related MCQs. The total marks to be allocated to this part will be 70 (out of 200). The candidates are requested to answer any 35 questions from the 40 questions. Two marks will be for each question.
Part 'C' may contain deep questions to test the candidate's knowledge of scientific concepts and/or application of the scientific concepts. The candidates are requested to answer any 25 questions from the 60 questions. The total marks to be allocated to this part will be 100 (out of 200). Four marks are to be awarded for each question.
* Negative mark will be 25% for each wrong answer.
CSIR NET June 2019 Mathematical Sciences Set B
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